# 本次美国CS代写主要是汇编assembly相关的代码实现

Introduction

CS-UY 2214 — Homework 8

Unless otherwise specified, put your answers in a plain text file named hw8.txt. Number each answer. Submit your work on Gradescope.

You may consult the E20 manual, which is available on Classes, under the Resources tab, in the “guides” folder.

Problems

1. Consider the following data structure in E20 assembly language:

array_size: .fill 10

array: .fill 5

.fill 1 .fill 4 .fill 2 .fill 9 .fill 6 .fill 5 .fill 8 .fill 0 .fill 7

The data structure describes an array of unsigned numbers, which begins at address array. In addition, the value at address array_size gives the length of the array.

Write an E20 assembly language program implementing the bubble sort algorithm. Your program will sort in place an array of arbitrary size. That is, after running your program, the values stored in sequence in memory, starting at address array, will be as follows:

0000 0001 0002 0004 0005 0005 0006 0007 0008 0009

The algorithm in pseudocode (via Wikipedia):

procedure bubbleSort(A : list of sortable items) n := length(A)

repeat
swapped := false

for i := 1 to n-1 inclusive do
/* if this pair is out of order */

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if A[i-1] > A[i] then
/* swap them and remember something changed */ swap(A[i-1], A[i])
swapped := true

end if end for

until not swapped end procedure

Your program must work not only with the above array, but with any array of numbers, of any size (> 0), that can be stored in E20 memory.

Your solution must be thoroughly commented, or else it will not be graded. Make sure that the comments help the grader understand the intent of your code. Test your solution in your simulator.

Put your answer (including the provided data structure) in a file named bubble.s.

1. Consider a virtual memory system with 40-bit virtual addresses, 16KB pages, and 36-bit physicaladdresses. Each memory cell is one byte.

What is the total size (in bytes) of the page table for each process? Include the protect, dirty, and valid bits for each page table entry. Assume that all virtual pages are used.

2. Consider a virtual memory system with 32-byte pages, 8-bit virtual addresses, and 8-bit physical addresses. The TLB is fully-associative, has 4 blocks, and uses LRU replacement. Each memory cell is one byte.Below, we show the initial state of the page table and TLB. Note that the Valid bit in the TLB refers to the validity of that TLB entry, not to the validity of the underlying page table entry: invalid pages are not cached.

Virtual page

0 1 2 3 4 5 6 7

Page table

V D P Physical page

1010 1004 0003 1104 1101 1001 1002 0005

TLB

V P Tag Value

1034 0
0
0

Starting from this initial state, determine what will happen for each of the following memory operations. For each memory operations, indicate if it causes a hit or a miss on the TLB. Then, indicate if it causes

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a page fault. If it doesn’t cause a page fault, indicate which physical address will be accessed. If the access causes a protection fault, say so.

WRITE to virtual address 53 READ from virtual address 32 WRITE to virtual address 5 READ from virtual address 98 READ from virtual address 64 READ from virtual address 80 WRITE to virtual address 100 WRITE to virtual address 35

4. Recall the principle of spatial locality, which states that memory locations that are nearby to each other are likely to be cached together.

Consider the following C++ code:

int a[2048] = {…}; int b[2048] = {…}; int c[2048];

for (i=0; i<2048; i++) c[i] = a[i] + b[i];

/* Make this
part faster */

Re-write the code to take advantage of cache effects relating to spatial locality. The goal of your revised code is to optimize the performance of the marked lines. The final effect of your revised code must be identical to the original. You may assume that any data structure that you create is initialized appropriately, as long as you state those assumptions.

Hint: you will have to restructure the data. You may want to use a struct.
I should point out that the following is NOT a valid solution, as it does not improve the spatial locality

of the addends:

struct array {
int a[2048] = {…};

};

int b[2048] = {…}; int c[2048];

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